Water enters through one end of a horizontal pipe of non-uniform cross-section with a velocity of 0.4m/s and leaves the other end with a velocity 0.6 m/s. The pressure of water at the first end is 1500N/m 2 . What is the pressure at the other end? (Density of water = 1.0 ´ ´ 10 3 kg/m 3 )
Text Solution
Verified by ExpertsThe correct answer is:
D
According to Bernoulli's theorem
P 1 + 
= P 2 + 
or, P 1 – P 2 = 
or, P 2 = P 1 − − 
Given: P 1 = 1500n/m 2 , v 1 = 0.4m/s, v 2 = 0.6 m/s,
P 2 =?
∴ ∴ P 2 = 1500 – 
´ ´ 1 ´ ´ 10 3 [(0.6) 2 – (0.4) 2 ]
or, P 2 = 1500 – 100 = 1400 N/m 2
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